Question

What mass of solute is contained in 20.0 ml of a 2.09 M barium acetate solution?

Answer 1

C_i=n/V --> n=C_i*V

m=n*M --> m=C_i*V*M

M(BaC₄H₆O₄)=137+12*4+1*6+16*4=255g/mol

m(BaC₄H₆O₄)= 2.09*0.02*255=10.66g

Answer: 10.66 g