Question

A. Use the Oxidation number method to balance the equation below.

MnO4-(aq) + H+ (aq) + Fe^2+ (aq) = Mn^2+ (aq) + Fe^3+ (aq) + H2O (l)

B. Which element was oxidized and which was reduced?

Oxidized:

Reduced:

Answer 1

A.Fe: +2 → +3;Change = +1

Mn: +7 → +2; Change = -5

MnO4-(aq) + 8H+ (aq) + 5Fe^2+ (aq) = Mn^2+ (aq) + 5Fe^3+ (aq) + 4H2O (l) 

B.

Oxidized:Fe

Reduced:Mn