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Answer to Question #90240 in Chemistry for Vaibhavi Desai
Question #90240
The oxidation states of vanadium in its compounds are V (+5), V (+4), V (+3) and V (+2). The vanadium (lll) ion can behave as a reductant or an oxidant.
(i) indicate on the following equation which reactant is the oxidant.
2V^3+ + Zn = 2V^2+ + Zn^2+
(i) indicate on the following equation which reactant is the oxidant.
2V^3+ + Zn = 2V^2+ + Zn^2+
Expert's answer
Zink (Zn) is an oxidant in this reaction.
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