Answer to Question #90188 in Chemistry for Vaibhavi Desai

Question

1.The oxidation states of vanadium in its compounds are V (+5), V (+4), V (+3) and V (+2). The vanadium (lll) ion can behave as a reductant or an oxidant.

(i) indicate on the following equation which reactant is the oxidant.

2V^3+ + Zn = 2V^2+ + Zn^2+

(ii) Which change in the following equation is oxidation?
Explain your choice.

V^3+ + Fe^3+ = V^4+ + Fe^2+

Answer 1

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