Answer to Question #90132 in Chemistry for Lilac marie

Question #90132
(a) Oxygen was formed at the anode and copper was formed at the cathode.

(i) The ionic half-equation for the formation of oxygen is shown.

4OH- = O2 + 2H2O + 4e-

Explain why this reaction is oxidation.

(ii) Write the ionic half-equation for the formation of copper at the cathode.

(b) The electrolysis was repeated using copper electrodes in place of carbon electrodes.

State and explain what happens to the masses of the anode and the cathode during this electrolysis.
1
Expert's answer
2019-05-27T07:57:21-0400
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