Task:
(a) What is the oxidation number of the named element in the following compounds?
(1) manganese in Mn2O7;
(2) Iron in [Fe(CN)6]3-.
Solution (1):
(1) Mn2O7
The oxidation state of the oxygen is -2, and the sum of the oxidation states is equal to zero.
2*n + 7*(-2) = 0;
2*n = 14;
n = +7.
The oxidation number of the Mn in Mn2O7 is +7.
Answer (1): Mn(+7).
Solution (2):
The oxidation state of the cyanide group (CN-) is -1, and the sum of the oxidation states is equal to the charge on the ion.
n + 6*(-1) = -3;
n = 6-3 = 3;
n = +3.
The oxidation number of the Fe(iron) in [Fe(CN)6]3- is +3.
Answer (2): Fe(+3).
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