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Question #89718
A girl with a mass of 45 kg is standing on a scale in a lift. What is the weight of the girl when (i) the lift is accelerating upwards at 2.0 ms s −2 and (ii) the lift is moving down with a constant velocity. Calculate the inertial force in each case.
Expert's answer
The weight of the girl in a lift
W
=
m
(
g
±
a
)
W=m(g \pm a)
W
=
m
(
g
±
a
)
(a)
Weight
W
=
45
k
g
×
(
9.8
m
/
s
2
+
2.0
m
/
s
2
)
=
531
N
W=45\:\rm{kg}\times(9.8\:\rm{m/s^2}+2.0\:\rm{m/s^2})=531\:\rm{N}
W
=
45
kg
×
(
9.8
m/
s
2
+
2.0
m/
s
2
)
=
531
N
Inertial force
F
i
=
W
−
m
g
=
531
N
−
441
N
=
90
N
F_i=W-mg=531\:\rm{N}-441\:\rm{N}=90\:\rm{N}
F
i
=
W
−
m
g
=
531
N
−
441
N
=
90
N
(b)
Weight
W
=
45
k
g
(
9.8
m
/
s
2
+
0
m
/
s
2
)
=
441
N
W=45\:\rm{kg}(9.8\:\rm{m/s^2}+0\:\rm{m/s^2})=441\:\rm{N}
W
=
45
kg
(
9.8
m/
s
2
+
0
m/
s
2
)
=
441
N
Inertial force
F
i
=
W
−
m
g
=
441
N
−
441
N
=
0
N
F_i=W-mg=441\:\rm{N}-441\:\rm{N}=0\:\rm{N}
F
i
=
W
−
m
g
=
441
N
−
441
N
=
0
N
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