Answer to Question #89718 in Chemistry for Jai

Question #89718
A girl with a mass of 45 kg is standing on a scale in a lift. What is the weight of the girl when (i) the lift is accelerating upwards at 2.0 ms s −2 and (ii) the lift is moving down with a constant velocity. Calculate the inertial force in each case.
1
Expert's answer
2019-05-15T05:47:50-0400

The weight of the girl in a lift

W=m(g±a)W=m(g \pm a)

(a)

Weight

W=45kg×(9.8m/s2+2.0m/s2)=531NW=45\:\rm{kg}\times(9.8\:\rm{m/s^2}+2.0\:\rm{m/s^2})=531\:\rm{N}


Inertial force


Fi=Wmg=531N441N=90NF_i=W-mg=531\:\rm{N}-441\:\rm{N}=90\:\rm{N}

(b)

Weight

W=45kg(9.8m/s2+0m/s2)=441NW=45\:\rm{kg}(9.8\:\rm{m/s^2}+0\:\rm{m/s^2})=441\:\rm{N}

Inertial force


Fi=Wmg=441N441N=0NF_i=W-mg=441\:\rm{N}-441\:\rm{N}=0\:\rm{N}


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