Answer to Question #89487 in Chemistry for Kendra Green

Question #89487

64.7mL of 0.45n sodium hydroxide to neutralize 45mL of acid.
Create 0.65m acid what is the percent and ph balance?

Expert's answer

C1V1=C2V2

C2 = 64.7*0.45/45 = 0.647 mol;

pH = -log[H+] = -log 0.647 = 0.19

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