Answer to Question #88704 in Chemistry for ashlee

Question #88704

A 885 mL NaCl solution is diluted to a volume of 1.04 L and a concentration of 6.00 mol/L . What was the initial concentration?

Expert's answer

n=Cм х V Cм=n/V

n (NaCl)=6 x 1.04 = 6.24 mol

Cм=6.24/0.885=7.05 mol

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