Question #88704
A 885 mL NaCl solution is diluted to a volume of 1.04 L and a concentration of 6.00 mol/L . What was the initial concentration?
Expert's answer
n=Cм х V Cм=n/V
n (NaCl)=6 x 1.04 = 6.24 mol
Cм=6.24/0.885=7.05 mol
