Answer to Question #88441 in Chemistry for koko

Question

if substance b has 51.45 g/mol how many grams are required to make 360.00mL of a 1.060 mol/L solution?

Answer 1

Task:

If substance B has 51.45 g/mol, how many grams are required to make 360.00mL of a 1.060 mol/L solution?

Solution:

360.00 mL = 0.36 L

n(B) = m(B) / M(B);

n(B) = C(B) * V(B);

Then,

m(B) / M(B) = C(B) * V(B);

m(B) / 51.45 = 1.060 * 0.36;

m(B) = 51.45 g/mol * 1.060 mol/L * 0.36 L = 19.63 g

m(B) = 19.63 g

Answer: 19.63 grams