Question

What is the mass in grams of 5.00 × 1022molecules of C9H8O4?

Answer 1

#85461 Chemistry, Other

What is the mass in grams of $5.00 \times 10^{22}$ molecules of $\mathrm{C}_{9} \mathrm{H}_{8} \mathrm{O}_{4}$?

Answer:

There are $6.022 \times 10^{23}$ molecules in a mole of a substance.

The number of moles of $\mathrm{C}_{9} \mathrm{H}_{8} \mathrm{O}_{4}$ is: $5.00 \times 10^{22} / 6.022 \times 10^{23} = 0.83 \times 10^{-1} = 0.083$ mol

$\mathrm{M}(\mathrm{C}_{9} \mathrm{H}_{8} \mathrm{O}_{4}) = 180 \mathrm{~g} / \mathrm{mol}$

$\mathrm{n} = \mathrm{m} / \mathrm{M} \quad \mathrm{m} = \mathrm{nM}$

$\mathrm{m}(\mathrm{C}_{9} \mathrm{H}_{8} \mathrm{O}_{4}) = 0.083 \times 180 = 14.94 \mathrm{~g}$

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