Chemical reaction:
3KOH + H3PO4 ⟶ K3PO4 + 3H2O
Mr (H3PO4)= 3(Ar(H)) + Ar(P) + 4(Ar(O))= 3 × 1+ 31 + 4 × 16 = 98 g/mol
Mr = M = 98 mol
m(H3PO4) = x = (98 mol × 1.71 mol) / (3 mol) = 55,86 g.
Answer: Mass of phosphoric acid, H3PO4 is 55,86 g.
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