Question

A 2.0 L flexible container holds 5.0 moles of oxygen (O2) gas. An additional 15.0 moles of nitrogen gas (N2) is added to the container. What is the new volume of the container?

Answer 1

Answer on Question #84754 – Chemistry – Other

Task:

A 2.0 L flexible container holds 5.0 moles of oxygen (O₂) gas. An additional 15.0 moles of nitrogen gas (N₂) is added to the container. What is the new volume of the container?

Solution:

Total volume = V(O₂) + V(N₂).

V(O₂) = 2.0 L; V(N₂) = X L.

If:

2.0 L = 5.0 moles

X L = 15.0 moles.

Then,

V(N₂) = X L = (15.0 moles) * (2.0 L) / (5.0 moles) = 6.0 L.

Finally,

Total volume = VTotal (container) = V(O₂) + V(N₂) = 2.0 L + 6.0 L = 8.0 L.

Total volume = 8.0 L.

Answer: 8.0 L is the new volume of the container.

Answer provided by www.AssignmentExpert.com