Question

What is the buffer concentration and PH of a mixture of 0.042M NaH2PO4 (pK=6.86) and 0.058 M Na2HPO4?

Answer 1

What is the buffer concentration and PH of a mixture of 0.042M NaH2PO4 (pK=6.86) and 0.058 M Na2HPO4?

**Solution.**

$$\mathrm{pH} = \mathrm{pK} + \lg C_{\mathrm{b}} / C_{\mathrm{ac}} = 6.86 + \lg (0.058 / 0.042) = 7$$ $$[ H^{+} ] = 10^{-7} \text{ mole/l}$$

**Answer.** pH = 7; [H⁺] = 10⁻⁷

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