Question

How many grams of carbon monoxide are needed to react with an excess of iron (III) oxide to produce 198.5 grams of iron? Fe2O3(s) + 3CO(g) ——> 3CO2(g) + 2Fe(s)

Answer 1

83813 Chemistry, Other

How many grams of carbon monoxide are needed to react with an excess of iron (III) oxide to produce 198.5 grams of iron? $\mathrm{Fe}_2\mathrm{O}_3(\mathrm{s}) + 3\mathrm{CO}(\mathrm{g}) \longrightarrow 3\mathrm{CO}_2(\mathrm{g}) + 2\mathrm{Fe}(\mathrm{s})$

Answer:

According to equation: $n(CO) = 3/2n(Fe)$

$n = m / M$

M (Fe) = 55.9 g/mol

M (CO) = 28 g/mol

n (Fe) = 198.5 / 55.9 = 3.6 mol

n (CO) = 3/2 x 3.6 = 5.4 mol

m (CO) = n x M = 5.4 x 28 = 151.2 g

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