Question #8273

Calculate the molar concentration of each ion (Na+ and PO4 3-) in a aqueous Na3PO4 solution when 2.0 g of Na3PO4 is dissolved in water so that the final volume of the solution is 150 ml.

Expert's answer

QUESTION:

Calculate the molar concentration of each ion (Na+ and PO4 3-) in a aqueous Na3PO4 solution when 2.0 g of Na3PO4 is dissolved in water so that the final volume of the solution is 150 ml.

SOLUTION:

nNa3PO4=mNa3PO4MNa3PO4=2.0 g164 g/mol=0.012 moln_{Na_3PO_4} = \frac{m_{Na_3PO_4}}{M_{Na_3PO_4}} = \frac{2.0\ g}{164\ g/mol} = 0.012\ molVsolution=0.15 LV_{\text{solution}} = 0.15\ LCNa3PO4=nNa3PO4Vsolution=0.012 mol0.15 L=0.081 molLC_{Na_3PO_4} = \frac{n_{Na_3PO_4}}{V_{\text{solution}}} = \frac{0.012\ mol}{0.15\ L} = 0.081\ \frac{mol}{L}


Assume that Na₃PO₄ is completely dissociated.


CNa+=3CNa3PO4=0.244 molLC_{Na^+} = 3C_{Na_3PO_4} = 0.244\ \frac{mol}{L}CPO42=CNa3PO4=0.081 molLC_{PO_4^{2-}} = C_{Na_3PO_4} = 0.081\ \frac{mol}{L}

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