Question

What mass of carbon dioxide is produced from the complete combustion of 3.10×10−3 g of methane?

Answer 1

Question #81812, Chemistry, Other

Question:

What mass of carbon dioxide is produced from the complete combustion of $3.10 \times 10^{-3} \, \text{g}$ of methane?

Solution:

Complete methane combustion can be described by the following equation:

$$\mathrm{CH_4} + 2\mathrm{O_2} \rightarrow \mathrm{CO_2} + 2\mathrm{H_2O}$$

From the equation, amount of $\mathrm{CH_4}$ equals the amount of carbon dioxide.

Number of moles ($\mathrm{CH_4}$ and $\mathrm{CO_2}$) equals:

$$\nu(\mathrm{CH_4}) = \nu(\mathrm{CO_2}) = \frac{m(\mathrm{CH_4})}{Mr(\mathrm{CH_4})} = \frac{3.10 \times 10^{-3} \, \text{g}}{16 \, \text{g/mol}} = 19.4 \times 10^{-5} \, \text{mol}$$

Next, the mass of carbon dioxide produced from the complete combustion of methane equals:

$$m(\mathrm{CO_2}) = \nu(\mathrm{CO_2}) \times Mr(\mathrm{CO_2}) = 19.4 \times 10^{-5} \, \text{mol} \times 44 \, \text{g/mol} = 8.54 \times 10^{-3} \, \text{g}$$

Answer:

Mass of carbon dioxide is $8.54 \times 10^{-3} \, \text{g}$

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