Question

Fe2O3+3Co->2Fe+3Co2
How many grams of iron can be produced from 10.50 of Fe2O3

Answer 1

#81369 Chemistry, Other

$\mathrm{Fe}_{2} \mathrm{O}_{3} + 3 \mathrm{CO} \rightarrow 2 \mathrm{Fe} + 3 \mathrm{CO}_{2}$

How many grams of Iron can be produced from 10.50 g of $\mathrm{Fe_2O_3}$ ?

Answer:

n (Fe) = 2 x n (Fe₂O₃)

n = m/M

M (Fe₂O₃) = 159.8 g/mol

n (Fe₂O₃) = 10.50/159.8 = 0.07 mol

n (Fe) = 2 x 0.07 = 0.14 mol

m (Fe) = n x M

M (Fe) = 55.8 g/mol

m (Fe) = 0.14 x 55.8 = 7.8 g

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