Question

Hydrogen and oxygen combine in a ratio of 1:8 to form water .indicate what will happen if we combine 14g hydrogen with 50g of oxyen.

Answer 1

Question #80909, Chemistry / Other

Hydrogen and oxygen combine in a ratio of 1:8 to form water. Indicate what will happen if we combine 14g hydrogen with 50g of oxygen.

Answer:

$$2 \mathrm{H}_{2} + \mathrm{O}_{2} = 2 \mathrm{H}_{2} \mathrm{O}$$ $$4 \mathrm{g} - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -$$ $$X = (14 \times 32) / 4$$ $$X = 112 \mathrm{g} \left(\mathrm{O}_{2}\right); \text{ not yet } 62 \mathrm{g} \text{ oxygen;}$$ 4 \mathrm{g} - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -} $$Y = (50 \times 4) / 32$$ $$Y = 6.25 \mathrm{g} \left(\mathrm{H}_{2}\right)$$

So we have $14 \mathrm{g} \mathrm{H}_{2}$ and remain $\mathrm{H}_{2} 7.75 \mathrm{g} (14-6.25)$ after reactions and $56.25 \mathrm{g}$ water is formed.

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