Question #80200

The specific heat capacity of silver is 0.24 J/°C·g.
(a) Calculate the energy required to raise the temperature of 160.0 g Ag from 273 K to 303 K.
______ J
(b) Calculate the energy required to raise the temperature of 1.0 mol Ag by 1.0°C (called the molar heat capacity of silver).
_____ J/mol°C
(c) It takes 1.15 kJ of energy to heat a sample of pure silver from 12.0°C to 15.1°C. Calculate the mass of the sample of silver.
____ in grams

Expert's answer

Question #80200

The specific heat capacity of silver is 0.24 J/°C·g.

(a) Calculate the energy required to raise the temperature of 160.0 g Ag from 273 K to 303 K.

☐ J

(b) Calculate the energy required to raise the temperature of 1.0 mol Ag by 1.0°C (called the molar heat capacity of silver).

☐ J/mol°C

(c) It takes 1.15 kJ of energy to heat a sample of pure silver from 12.0°C to 15.1°C. Calculate the mass of the sample of silver.

☐ in grams

Answer:

According to the equation Q=CΔTmQ = C^{*} \Delta T^{*} m:

(a) ΔT=303K273K=30C\Delta T = 303K - 273K = 30^{\circ}C

Q=0.2430160=1152JQ = 0.24 * 30 * 160 = 1152 \, \text{J}

So, the right answer is 1152 J.

(b) ΔT=1C\Delta T = 1^{\circ}C

1 mole of Ag = 108 g of Ag

Q=0.241108=25.92JQ = 0.24 * 1 * 108 = 25.92 \, \text{J}

C = 25.92 J/mol°C

So, the right answer is 25.92 J/mol°C.

(c) ΔT=15.1C12.0C=3.1C\Delta T = 15.1^{\circ}C - 12.0^{\circ}C = 3.1^{\circ}C

m=Q/(CΔT)=1.151000/(0.243.1)=1545.7gm = Q / (C^{*} \Delta T) = 1.15 * 1000 / (0.24 * 3.1) = 1545.7 \, \text{g}

So, the right answer is 1545.7 g.


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