Question

What is the pOH if the Molarity of NaOH is 2.3X10^-11

Answer 1

#77483 Chemistry, Other

What is the pOH if the Molarity of NaOH is $2.3 \cdot 10^{-11}$.

**Answer:**

NaOH is a strong base. Therefore, its pOH is correlated with its molarity directly:

$$\mathrm{pOH} = -\lg [\mathrm{OH}^\prime] = -\lg [2.3 \cdot 10^{-11}] = 10.64$$

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