Question #77392
If 50.0 mL of 12.0 M of nitric acid is prepared with 0.100 M nitric acid, what will the new volume be?
Expert's answer
Answer:
Cm1V1 = Cm2V2, where
Cm - molar concentration, V - volume of nitric acid
12*50 = x*0.1
x = 6000 ml
Cm1V1 = Cm2V2, where
Cm - molar concentration, V - volume of nitric acid
12*50 = x*0.1
x = 6000 ml
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#339914 on Dec 2023
#339914 on Dec 2023