Question #77208, Chemistry / Other
A buffer is created by dissolving 0.450 mol of sodium ascorbate (NaC₆H₇O₆) and 0.500 mol of ascorbic acid (HC₆H₇O₆) in enough water to create 1.00 L of solution.. a) what is the original pH of the buffer
Solution:
Henderson–Hasselbalch equation:
pH=pKa+log[HA][A−][A−]=V(solution)n(A−)=1.00 L0.500 mol=0.500 Lmol[HA]=V(solution)n(HA)=1.00 L0.450 mol=0.450 Lmol
pKa (first) for ascorbic acid is 4.10.
Using values:
pH=4.10+log0.450 Lmol0.500 Lmol=4.10+0.05=4.15Answer:
4.15
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