Question #77208

A buffer iscreated by dissolving 0.450mol of sodium ascorbate(NaC6H7O6)and 0.500mol of ascorbic acid(HC6H7O6)in enough water to create 1.00Lof solution.. a) what is the original pH of the buffer

Expert's answer

Question #77208, Chemistry / Other

A buffer is created by dissolving 0.450 mol of sodium ascorbate (NaC₆H₇O₆) and 0.500 mol of ascorbic acid (HC₆H₇O₆) in enough water to create 1.00 L of solution.. a) what is the original pH of the buffer

Solution:

Henderson–Hasselbalch equation:


pH=pKa+log[A][HA]pH = pK_a + \log \frac{[A^-]}{[HA]}[A]=n(A)V(solution)=0.500 mol1.00 L=0.500 molL[A^-] = \frac{n(A^-)}{V(solution)} = \frac{0.500\ mol}{1.00\ L} = 0.500\ \frac{mol}{L}[HA]=n(HA)V(solution)=0.450 mol1.00 L=0.450 molL[HA] = \frac{n(HA)}{V(solution)} = \frac{0.450\ mol}{1.00\ L} = 0.450\ \frac{mol}{L}


pKa (first) for ascorbic acid is 4.10.

Using values:


pH=4.10+log0.500 molL0.450 molL=4.10+0.05=4.15pH = 4.10 + \log \frac{0.500\ \frac{mol}{L}}{0.450\ \frac{mol}{L}} = 4.10 + 0.05 = 4.15

Answer:

4.15

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