Question

Chloroform (CHCl3), an important solvent, is produced by a reaction between methane and chlorine.
CH4(g) + 3 Cl2(g) CHCl3(g) + 3 HCl(g)
How many grams of CH4 is needed to produce 37.5 g CHCl3?

Answer 1

Answer on Question #76590 – Chemistry – Other

Task:

Chloroform (CHCl₃), an important solvent, is produced by a reaction between methane and chlorine.

$$\mathrm{CH_4}(g) + 3\mathrm{Cl_2}(g) = \mathrm{CHCl_3}(g) + 3\mathrm{HCl}(g)$$

How many grams of CH₄ is needed to produce 37.5 g CHCl₃?

Solution:

$$M(CH_4) = 16.04 \, \mathrm{g/mol};$$ $$M(CHCl_3) = 119.38 \, \mathrm{g/mol}.$$

The reaction equation:

$$\mathrm{CH_4}(g) + 3\mathrm{Cl_2}(g) = \mathrm{CHCl_3}(g) + 3\mathrm{HCl}(g)$$

By the equation of the chemical reaction: $n(\mathrm{CH_4}) = n(\mathrm{CHCl_3})$.

$$n(CH_4) = \frac{m(CH_4)}{M(CH_4)}$$ $$n(CHCl_3) = \frac{m(CHCl_3)}{M(CHCl_3)}.$$

Then,

$$\frac{m(CH_4)}{M(CH_4)} = \frac{m(CHCl_3)}{M(CHCl_3)};$$ $$m(CH_4) = \frac{m(CHCl_3) * M(CH_4)}{M(CHCl_3)};$$ $$m(CH_4) = \frac{37.5 * 16.04}{119.38} = 5.038 \approx 5.04 \, \mathrm{g}$$

Answer: $m(\mathrm{CHCl_3}) = 5.04 \, \mathrm{g}$

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