Question

When 84.8g of iron (III) oxide reacts with 53.0g Of CO how many grams of FE are produced?
fe2o3 + 3co -> 2fe + 3co2

Answer 1

#76500 Chemistry, Other

When 84.8 g of iron (III) oxide reacts with 53.0 g of CO how many grams of Fe are produced?

Fe₂O₃ + 3CO → 2Fe + 3CO₂

Answer:

According to this reaction, n (Fe) = 2 n (Fe₂O₃) = 2/3 (CO)

n = m/M

M (Fe₂O₃) = 160 g/mol

M (CO) = 26 g/mol

M (Fe) = 55.9 g/mol

n (Fe₂O₃) = 84.8/160 = 0.53 mol

n (CO) = 53.0 / 26 = 2.0 mol

Fe₂O₃ is a limiting reagent here. Therefore:

n (Fe) = 2 n (Fe₂O₃) = 2 · 0.53 = 1.06 mol

m (Fe) = 1.06 · 55.9 = 59.3 g