#76133 Chemistry, Other
An element with molar mass 63 g/mol forms a cubic unit cell with edge length of 360.8 pm if its density is 8.92 g/cm³. What is the nature of the cubic unit cell.
Answer:
d = (n × M) / (a³ × Nₐ)
where d – density of crystal;
n – number of atoms in crystal;
M – atomic mass;
Nₐ – Avogadro number.
8.92 = (n × 63) / ((3.608 × 10⁻⁸)³ × 6.022 × 10²³)
From this n ≈ 4
4 atoms in the crystal indicates that cubic unit cell is hexagonal with close packing.
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