Guys please help me with this problem, thanks in advanced! 200 mg of KOH are added with H2O until a final volume of 720 ml is reached. Determine the pH of the solution obtained and tell if the solution is acidic or basic.
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Expert's answer
2018-04-16T11:02:08-0400
pH = -lg [H+] СM = n/V n = m/M pH + pOH = 14 M (KOH) = 56.1 g/mol n (KOH) = 0.2/56.1 = 0.004 mol СM = 0.004 / 0.72 = 0.005 mol/l pOH = - lg [0.005] = 2.3 pH = 14 – 2.3 = 11.7 The solution will be basic.
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