What is the concentration of a solution of a volume of 2.5 liters containing 660 grams of calcium phosphate?
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Expert's answer
2018-04-07T07:59:10-0400
The solubility of Ca3(PO4)2 is 0.002 g/100 g 2.5 L = 2.5 kg = 2500 g 0.002 g dissolves in 100 g x g dissolves in 2500 g x = 0.05 g So only 0.05 g will be dissolved! 0.05 g / 310.2 g / mol / 2.5 L = 6.45 x 10-5 M
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