Question #75632
What is the concentration of a solution of a volume of 2.5 liters containing 660 grams of calcium phosphate?
Expert's answer
The solubility of Ca3(PO4)2 is 0.002 g/100 g
2.5 L = 2.5 kg = 2500 g
0.002 g dissolves in 100 g
x g dissolves in 2500 g
x = 0.05 g
So only 0.05 g will be dissolved!
0.05 g / 310.2 g / mol / 2.5 L = 6.45 x 10-5 M
Answer: 6.45 x 10-5 M.
2.5 L = 2.5 kg = 2500 g
0.002 g dissolves in 100 g
x g dissolves in 2500 g
x = 0.05 g
So only 0.05 g will be dissolved!
0.05 g / 310.2 g / mol / 2.5 L = 6.45 x 10-5 M
Answer: 6.45 x 10-5 M.
