Question #75128

Find 2.28e+5 kg NH3 in liters at STP

Expert's answer

Question #75128, Chemistry / Other / Completed

Find 2.28e+5 kg NH3 in liters at STP

Solution:

n = 2.28x10⁵ kg / 17.031 kg/kmol = 13387.35 kmol

V = n · Vm = 13387.35 kmol x 22.4 m³/kmol = 299876.7 m³ = 299876700 L ≈ 3 x 10⁸

Answer: 3 · 10⁸ L.

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