Question #72435

A 0.10 M solution of HF has a pH of 2.10. Calculate the Ka of HF.

Expert's answer

#72435 Chemistry, Other

A 0.10 M solution of HF has a pH of 2.10. Calculate the Ka of HF.

Answer:


-log Ka=-log [H3O+]pKa=pHKa=10pKaKa=102.10Ka=0.0076\begin{array}{l} \text{-log } \mathrm{K_a} = \text{-log } [\mathrm{H_3O^+}] \\ \mathrm{p K_a} = \mathrm{p H} \\ \mathrm{K_a} = 10^{-p \mathrm{K_a}} \\ \mathrm{K_a} = 10^{-2.10} \\ \mathrm{K_a} = 0.0076 \\ \end{array}


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