#68662 Chemistry, Other
How many spectator ions are found in the chemical reaction between aluminum oxide and sulfuric acid?
Answer:
A l 2 O 3 + 3 H 2 S O 4 → I + C A l 2 ( S O 4 ) 3 + 3 H 2 O A l 2 O 3 + 6 H + + 3 S O 4 / → I + C 2 A l + + + + 6 S O 4 / + 3 H 2 O \begin{array}{l}
\mathrm{Al_2O_3} + 3 \mathrm{H_2SO_4} \xrightarrow{\mathrm{I^+C}} \mathrm{Al_2(SO_4)_3} + 3 \mathrm{H_2O} \\
\mathrm{Al_2O_3} + 6 \mathrm{H^+} + 3 \mathrm{SO_4} \quad / \quad \xrightarrow{\mathrm{I^+C}} 2 \mathrm{Al^{+++}} + 6 \mathrm{SO_4} \quad / \quad + 3 \mathrm{H_2O} \\
\end{array} A l 2 O 3 + 3 H 2 S O 4 I + C A l 2 ( S O 4 ) 3 + 3 H 2 O A l 2 O 3 + 6 H + + 3 S O 4 / I + C 2 A l +++ + 6 S O 4 / + 3 H 2 O
A spectator ion is an ion that exists as a reactant and a product in a chemical equation.
Therefore, in this reaction there is 1 spectator ion - S O 4 / / \mathrm{SO_4}^{/ / } S O 4 // .
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