A 0.817G SAMPLE OF METAL WAS HEATED IN AIR TO FORM THE OXIDE. THE OXIDE WEIGHED 0.933G. BY ASSUMING THAT THE METAL ATOMS COMBINE WITH OXYGEN ATOMS IN A 1:1 RATIO, CALCULATE THE ATOMIC WEIGHT OF THE METAL
0.817 0.933
Me + o2=MeO2
x
x+32
0.817*(x+32)=0.933x
0.817x + 24.177 =
0.933x
24,177=0.933x-0.817x
24.177=0.116x
x=208
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