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Answer to Question #67904 in Chemistry for Irshad
Question #67904
A chemist (using diffusion apparatus) was working on a gas of unknown identity.using diffusion apparatus.He noted that the rate of diffusion of the unknown gas was 70.3cm3/s where asCO2 is 60 cm3/s under similar conditions.What is the molecular mass and identity of unknown gas?
Expert's answer
rate 1 / Rate 2 = square root ( M2 / M1 )
M (CO 2 ) = 44 g/mol
70.3/60 = square root (44 / x)
M1 = 32 g/mol
Therefore, gas 1 is O 2 .
M (CO 2 ) = 44 g/mol
70.3/60 = square root (44 / x)
M1 = 32 g/mol
Therefore, gas 1 is O 2 .
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