In an experiment 0.197 g of gold metal reacts to yield 0.303g of gold (III) chloride. Using the conservation of mass law, predict the mass of reacting chlorine gas
Au(s)+Cl2(g)=2AuCl3(s)
m (Au) + m (Cl 2 ) = m (AuCl 3 )
m (Cl 2 ) = 0.303 – 0.197 = 0.106 g
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