Question #67084
An automatic gun fires ' n ' bullets with a speed of 1800 m/ sec in 3 seconds. The mass of each bullet is 25 gm. If 450N force is required to hold the gun in position.Find the number of bullets fired in each second.
Expert's answer
Force exerted by n bullets is 450 N (as the system remains stable).
Force exerted by n bullets: F=ma 450=25*10-3*a a=18000 m/s2
v=u+at
Initial velocity of a bullet is u=0 m/s
Final velocity of a bullet v=1800 m/s
1800=18000·t
t = 0.1 s (time taken for 1 bullet to be fired)
Number of bullets: 3/0.1=30.
Force exerted by n bullets: F=ma 450=25*10-3*a a=18000 m/s2
v=u+at
Initial velocity of a bullet is u=0 m/s
Final velocity of a bullet v=1800 m/s
1800=18000·t
t = 0.1 s (time taken for 1 bullet to be fired)
Number of bullets: 3/0.1=30.
