An automatic gun fires ' n ' bullets with a speed of 1800 m/ sec in 3 seconds. The mass of each bullet is 25 gm. If 450N force is required to hold the gun in position.Find the number of bullets fired in each second.
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Expert's answer
2017-04-03T11:00:07-0400
Force exerted by n bullets is 450 N (as the system remains stable). Force exerted by n bullets: F=ma 450=25*10-3*a a=18000 m/s2 v=u+at Initial velocity of a bullet is u=0 m/s Final velocity of a bullet v=1800 m/s 1800=18000·t t = 0.1 s (time taken for 1 bullet to be fired) Number of bullets: 3/0.1=30.
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