Question

A chemist requires 0.423 mol Na2CO3 for a reaction. How many grams does this correspond to?

Answer 1

Answer on Question #65278 - Chemistry - Other

Task:

A chemist requires 0.423 mol $\mathrm{Na_2CO_3}$ for a reaction. How many grams does this correspond to?

Solution:

Sodium carbonate $(\mathrm{Na_2CO_3})$ has a molar mass equal to 105.9888 g/mol.

On this basis,

1 mol $\mathrm{Na_2CO_3}$ has a mass equal to 105.9888 g;

0.423 mol $\mathrm{Na_2CO_3}$ has a mass equal to X g.

Then,

$$X = m(\mathrm{Na_2CO_3}) = \frac{0.423\,\mathrm{mol} \times 105.9888\,\mathrm{g}}{1\,\mathrm{mol}} = 44.8333\,\mathrm{g}.$$

Answer: 44.8333g grams does this correspond to 0.423 mol $\mathrm{Na_2CO_3}$

Answer provided by www.AssignmentExpert.com