Answer to Question #64897 in Chemistry for mhanad

Question

describe the preparation of 100ml of 0.1 M HCl from a concentrated solution that has a specific gravity of 1.18 and is 37%(w/w) HCl ?

Answer 1

(1000 mL/ 1L)(1.18 g/mL) · (0.37) · (1mol HCl/36.5 g HCl) = 11.96 M
We want to make 100 mL of 0.1 M: 100 mmol HCl required
V x M = V x M 100 mL x 0.1 mmol/mL = V x 11.96 M
V = 0.84 mL
Therefore, take 0.84 mL of the conc. HCl and dilute to 100.0 mL with water.