Question #64514

what is the percent composition of PbCl2?

Expert's answer

Answer on Question #64514 - Chemistry - Other

Task:

What is the percent composition of PbCl2\mathrm{PbCl}_2?

Solution:

Standard atomic weight:


Ar(Pb)=207.2;Ar(Pb) = 207.2;Ar(Cl)=35.45;Ar(Cl) = 35.45;


We find the molar mass PbCl2:


M(PbCl2)=Ar(Pb)+2×Ar(Cl)=207.2+2×35.45=278.1 g/molM(PbCl_2) = Ar(Pb) + 2 \times Ar(Cl) = 207.2 + 2 \times 35.45 = 278.1\ g/mol


Then,


w(Pb)=Ar(Pb)M(PbCl2)×100%=207.2278.1×100%=74.5%;w(Pb) = \frac{Ar(Pb)}{M(PbCl_2)} \times 100\% = \frac{207.2}{278.1} \times 100\% = 74.5\%;w(Cl)=2×Ar(Cl)M(PbCl2)×100%=2×35.45278.1×100%=25.5%.w(Cl) = \frac{2 \times Ar(Cl)}{M(PbCl_2)} \times 100\% = \frac{2 \times 35.45}{278.1} \times 100\% = 25.5\%.


Answer:

Percent composition of PbCl2\mathrm{PbCl}_2: 74.5% Pb and 25.5% Cl.

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