Question

what mass of magnesium hydroxide would be required for the magnesium hydroxide to react to the equivalence point with 558 mL of 3.18 M hydrochloric acid

Answer 1

Answer to Question #62312, Chemistry / Other

what mass of magnesium hydroxide would be required for the magnesium hydroxide to react to the equivalence point with 558 mL of 3.18 M hydrochloric acid

Answer:

$$\mathrm{Mg(OH)_2} + 2\mathrm{HCl} = \mathrm{MgCl_2} + 2\mathrm{H_2O}$$

If you are given 558 mL of 3.18 M of HCl, to find the mass of the $\mathrm{Mg(OH)_2}$, we can use dimensional analysis and equation coefficients to convert volume of HCl to moles of HCl, to moles of $\mathrm{Mg(OH)_2}$, to grams of $\mathrm{Mg(OH)_2}$:

$$m = \frac{558\ \mathrm{mL\ HCl}}{1\ \mathrm{mL}} \times 1L \times \frac{3.18\ \mathrm{mol/L}}{1000\ \mathrm{mL}} \times \frac{1\ \mathrm{mol\ Mg(OH)_2}}{2\ \mathrm{mol\ HCl}} \times \frac{58.319\ \mathrm{g\ KBr}}{1\ \mathrm{mol\ Mg(OH)_2}} = 51.74\ \mathrm{g}$$

51.74 g Mg(OH)₂

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