Question #62244

when an irregularly shaped chunk of an unknown metal, weighing 8.763g, was placed in a graduated cylinder containing 25.0ml of water, the water level in the cylinder rose to 28.76ml. what is the density of this unknown metal in g\cm3?

Expert's answer

Answer on the question #62244, Chemistry / Other

Question:

when an irregularly shaped chunk of an unknown metal, weighing 8.763g, was placed in a graduated cylinder containing 25.0ml of water, the water level in the cylinder rose to 28.76ml. what is the density of this unknown metal in g\cm³?

Solution:

According to definition, the density is the ratio of mass and volume of the object:


d=mVd = \frac {m}{V}


The volume of the object can be calculated as the difference of the water levels:


V=VfVi=28.76ml25.0ml=3.76ml=3.76cm3V = V _ {f} - V _ {i} = 28.76 \text{ml} - 25.0 \text{ml} = 3.76 \text{ml} = 3.76 \text{cm}^3d=8.763g3.76cm3=2.331g/cm3d = \frac {8.763 \text{g}}{3.76 \text{cm}^3} = 2.331 \text{g/cm}^3


Answer: 2.331 g/cm³

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