Question

A 1.000-g sample of pure organic compound was allowed to react with excess Na2O3 to form NaCl. The resulting sample was precipitated with excess AgNO3 giving 1.950 AgCl. If the MW of the compound is 147, how many Chlorine atom does each molecule contain?

Answer 1

Answer on the question #62078, Chemistry / Other

Question:

A 1.000-g sample of pure organic compound was allowed to react with excess Na2O3 to form NaCl. The resulting sample was precipitated with excess AgNO3 giving 1.950 AgCl. If the MW of the compound is 147, how many Chlorine atom does each molecule contain?

Solution:

First, let's calculate the number of the moles of the organic compound. It is equal to its ratio of mass and molar mass:

$$n(\text{organic}) = \frac{m}{M} = \frac{1.000g}{147\ g/mol} = 6.8 \cdot 10^{-3}\ m \text{Cl}.$$

Then, we can get the number of the moles of chlorine:

$$n(Cl) = n(AgCl) = \frac{m(AgCl)}{M(AgCl)} = \frac{1.950\ g}{143.32\ g/mol} = 0.0136\ mol.$$

Thus, $6.8 \cdot 10^{-3}$ mol of organic compound contains 0.0136 of chlorine. One mole of organic compound contains:

$$\frac{n(Cl)}{n(\text{organic})} = \frac{0.0136}{6.8 \cdot 10^{-3}} = 2.0$$

Each molecule of organic compound contains 2 chlorine atoms.

Answer: Each molecule of organic compound contains 2 chlorine atoms.

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