Question

4.90g of kclo3on heating shows a weught loss of 0.384g what percentage of the original kclo3 has decomposed

Answer 1

Question #61546, Economics, Other

4.90 g of KClO₃ on heating shows a weight loss of 0.384 g. What percentage of the original KClO₃ has decomposed.

Answer:

2KClO₃ → heat → 2KCl + 3O₂

2 mol KClO₃ produce 3 mol O₂

The 0.384 g mass loss was due to the oxygen generated.

The amount of moles of oxygen generated can be calculated as:

Molar mass O₂ = 32 g/mol

0.384 g O₂ = 0.384/32 = 0.012 mol O₂ generated

This came from the decomposition of 0.012·2/3 = 0.008 mol of KClO₃

Molar mass KClO₃ = 122.55 g/mol

0.008 mol KClO₃ = 0.008·122.55 = 0.9804 g KClO₃ decomposed

% of original sample: 0.9804/4.90·100 = 20.0%

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