Question #60581, Chemistry, Other
Sodium carbonate reacts with HCl acid to liberate CO2. Find the number of moles of CO2. Also find the volume obtained at STP when 1 mole of sodium bicarbonate is used.
Answer:
Na2CO3+2HCl=H2O+CO2+2NaCl
According to the equation, the number of moles of CO2 formed is 1.
n(Na2CO3)=n(CO2)=1 mole
n(CO2)=V/22.4
V(CO2)=1⋅22.4=22.4 l
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