Question #60581

Sodium carbonate reacts with HCl acid to liberate CO2. Find the number of moles of CO2.Also find the volume obtained at STP when 1 mole of sodium bicarbonate is used.

Expert's answer

Question #60581, Chemistry, Other

Sodium carbonate reacts with HCl acid to liberate CO2\mathrm{CO}_{2}. Find the number of moles of CO2\mathrm{CO}_{2}. Also find the volume obtained at STP when 1 mole of sodium bicarbonate is used.

Answer:

Na2CO3+2HCl=H2O+CO2+2NaCl\mathrm{Na}_{2}\mathrm{CO}_{3} + 2\mathrm{HCl} = \mathrm{H}_{2}\mathrm{O} + \mathrm{CO}_{2} + 2\mathrm{NaCl}

According to the equation, the number of moles of CO2\mathrm{CO}_{2} formed is 1.

n(Na2CO3)=n(CO2)=1 mole\mathrm{n(Na_2CO_3) = n(CO_2) = 1\ mole}

n(CO2)=V/22.4\mathrm{n(CO_2) = V / 22.4}

V(CO2)=122.4=22.4 l\mathrm{V(CO_2) = 1\cdot 22.4 = 22.4\ l}

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