Question

TITRATION LAB:
Q: what is the concentration of acid in asprin?
The Balanced equation is this:
HC9H7O4 + NaOH------>H2O + NaC9H7O4
Here is the data table:
Trial 1 Trial 2 Trial 3 Trial 4
Mass of Asprin (g) 0.6g 0.59g 0.6g 0.57g
Initial volume of NaOH(ml) 0.5ml 14ml 27.7ml 8.7ml
Final volume of NaOH(ml) 14ml 27.7ml 40.9ml 18.7ml

Show me the calculations for all four trials step by step.

Answer 1

#60327 Chemistry, Other

TITRATION LAB:

Q: what is the concentration of acid in aspirin?

The Balanced equation is this:

$$\mathrm {H C} _ {9} \mathrm {H} _ {7} \mathrm {O} _ {4} + \mathrm {N a O H} \rightarrow \mathrm {H} _ {2} \mathrm {O} + \mathrm {N a C} _ {9} \mathrm {H} _ {7} \mathrm {O} _ {4}$$

Here is the data table:

Answer:

$$n \left(H C _ {9} H _ {7} O _ {4}\right) = n (N a O H)$$ $$C _ {M} \left(H C _ {9} H _ {7} O _ {4}\right) \cdot V \left(H C _ {9} H _ {7} O _ {4}\right) = n \left(H C _ {9} H _ {7} O _ {4}\right) = C _ {M} (N a O H) \cdot V (N a O H)$$

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