Question

calculate the titer in mg CaCO3/mL of an edta solution with molar concentration 0,0100 M.

Answer 1

Answer on the question #59897, Chemistry / Other

Question:

calculate the titer in mg CaCO₃/mL of an edta solution with molar concentration 0.0100 M.

Solution:

Molar mass of CaCO₃ is:

$$M(CaCO_3) = 100.0869 \ g \ mol^{-1}$$

CaCO₃ reacts with edta with 1:1 molar ratio:

$$CaCO_3 + Y^{4-} \rightarrow CaY^{2-} + CO_3^{2-}$$

Then, to calculate the titer of edta solution in mg CaCO₃/mL, we just calculate what would be concentration of CaCO₃ in mg/mL, if molar concentration is 0.0100 mol/L:

$$t = c \cdot M = 0.0100 \ (mol \ L^{-1}) \cdot 100.0869 \ (g \ mol^{-1}) = 1.001 \ g \ L^{-1}, \text{or } 1.001 \ mg/mL$$

Answer: 1.001 mg/mL

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