Question

What is the molarity of a 500 mL solution containing 249 g of KI?

Answer 1

Answer on Question #58834 - Chemistry - Other

Task:

What is the molarity of a 500 mL solution containing 249 g of KI?

Solution:

The molarity of a solution is calculated by taking the moles of solute and dividing by the liters of solution:

$$Molarity = \frac{moles\ of\ solute}{liters\ of\ solution}.$$

Then,

$$M (KI) = 39 + 127 = 166\ (g/mol);$$ $$n (KI) = m (KI) / M (KI) = 249 / (39 + 127) = 249 / 166 = 1.50\ (mol);$$ $$V (solution) = 500\ ml = 0.5\ l;$$

Then,

$$C (KI) = n (KI) / V (solution) = 1.50\ mol / 0.5\ l = 3.00\ mol/l;$$

Answer:

Molarity (KI) = C (KI) = 3 mol/l.

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