Question

How many grams of ethane gas (C2H6) are in a 12.7 liter sample at 1.6 atmospheres and 24°C? Show all work used to solve this problem.

Answer 1

Answer on Question #57335 - Chemistry - Other

Question:

How many grams of ethane gas (C2H6) are in a 12.7 liter sample at 1.6 atmospheres and $24^{\circ}\mathrm{C}$? Show all work used to solve this problem.

Answer:

Using Mendeleev-Clapeyron equation we can find the mass of given gas:

$$P V = \frac {m}{M} \times R T,$$

where $P$ – the pressure, $V$ – the volume, $T$ – the absolute temperature [T(K) = 273 + T(°C)], $m$ – the mass and $M$ – the molecular weight, $R$ – universal gas constant ($R = 0.082057338(47) \, \text{L} \, \text{atm/(K mol)}$).

According to this, the mass of ethane is defined:

$$m = \frac {M}{R T} \times P V, \text{ where}$$ $$M(\text{ethane}) = 12 + 12 + 6 = 30 \, \text{g/mol}$$ $$T = 273 + 24 = 297 \, \text{K}$$ $$P = 1.6 \, \text{atm}$$ $$V = 12.7 \, \text{L}$$

Hence, the mass of ethane is:

$$m = \frac {30}{0.08206 \times 297} \times 1.6 \times 12.7 = 25.013 \, \text{g}$$

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