Question

A student analyzes a sample and finds out it contains 25% of NaCl. After that he realises the sample contained KCl instead of NaCl. What is the % concentration of KCl in the sample?

Answer 1

Answer to Question #57222 - Chemistry - Other

Question:

A student analyzes a sample and finds out it contains 25% of NaCl. After that he realises the sample contained KCl instead of NaCl. What is the % concentration of KCl in the sample?

Solution:

Mr(NaCl) = 58.44

Mr(KCl) = 74.55

$$\frac{w(NaCl)}{w(KCl)} = \frac{M_r(NaCl)}{M_r(KCl)}$$ $$w(KCl) = \frac{M_r(KCl) \times w(NaCl)}{M_r(NaCl)}$$ $$w(KCl) = \frac{74.55 \times 25}{58.44} = 31.9\%$$

Answer:

31.9 %

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