Question #56950
What is the half-reaction for the reduction of oxygen that occurs with the corrosion of iron? Using this reaction, explain why corrosion occurs more slowly in dry climates
Expert's answer
Half-reaction for the reduction of oxygen:
O2 + 4e- + 4H+ → 2H2O E0O/4OH-=+1.23 V
As we have seen in the reactions involving hydrogen ions. Supplier of hydrogen ions is water. With an increase pH to 9-10, corrosion reaction practically stops. Therefore, the reaction occurs in the presence of oxygen dissolved in water, the water takes on the role of the electrolyte.
O2 + 4e- + 4H+ → 2H2O E0O/4OH-=+1.23 V
As we have seen in the reactions involving hydrogen ions. Supplier of hydrogen ions is water. With an increase pH to 9-10, corrosion reaction practically stops. Therefore, the reaction occurs in the presence of oxygen dissolved in water, the water takes on the role of the electrolyte.
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#339914 on Dec 2023
#339914 on Dec 2023