Question #56562

When 2.40 moles of tricarbon octahydride are combusted, how many grams of water and carbon dioxide are formed?

Expert's answer

Answer on Question #56562 – Chemistry - Other

Question:

When 2.40 moles of tricarbon octahydride are combusted, how many grams of water and carbon dioxide are formed?

Answer:

C3H8+5O2=4H2O+3CO2\mathrm{C_3H_8} + 5\mathrm{O_2} = 4\mathrm{H_2O} + 3\mathrm{CO_2}v=mMv = \frac{m}{M}M(H2O)=18.01 g/molM(\mathrm{H_2O}) = 18.01\ \mathrm{g/mol}M(CO2)=43.99 g/molM(\mathrm{CO_2}) = 43.99\ \mathrm{g/mol}v(H2O)=4v(C3H8)v(\mathrm{H_2O}) = 4 \cdot v(\mathrm{C_3H_8})m(H2O)=vM=2.40418.01=172.89 gm(\mathrm{H_2O}) = vM = 2.40 \cdot 4 \cdot 18.01 = 172.89\ \mathrm{g}v(CO2)=3v(C3H8)v(\mathrm{CO_2}) = 3 \cdot v(\mathrm{C_3H_8})m(CO2)=vM=2.40343.99=316.73 gm(\mathrm{CO_2}) = vM = 2.40 \cdot 3 \cdot 43.99 = 316.73\ \mathrm{g}


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