Answer on Question #56562 – Chemistry - Other
Question:
When 2.40 moles of tricarbon octahydride are combusted, how many grams of water and carbon dioxide are formed?
Answer:
C3H8+5O2=4H2O+3CO2v=MmM(H2O)=18.01 g/molM(CO2)=43.99 g/molv(H2O)=4⋅v(C3H8)m(H2O)=vM=2.40⋅4⋅18.01=172.89 gv(CO2)=3⋅v(C3H8)m(CO2)=vM=2.40⋅3⋅43.99=316.73 g
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